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The first way works for a list or a string This means that list is not the same as list, even though customer is a subtype of object. The second way only works for a list, because slice assignment isn't allowed for strings
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Other than that i think the only difference is speed You can't directly cast list to list because java generics are invariant It looks like it's a little faster the first way
Try it yourself with timeit.timeit () or preferably timeit.repeat ().
The first, [:], is creating a slice (normally often used for getting just part of a list), which happens to contain the entire list, and thus is effectively a copy of the list The second, list(), is using the actual list type constructor to create a new list which has contents equal to the first list. Given a dataframe, i want to groupby the first column and get second column as lists in rows, so that a dataframe like A b a 1 a 2 b 5 b 5 b 4 c 6 becomes a [1,2] b [5,5,4] c [6] how do i do this?
Model status certified —models are expected to work with chromeos flex Minor issues expected —models are likely to support at least basic functionality, but are still being worked on by our team You might run into minor issues If your list of lists comes from a nested list comprehension, the problem can be solved more simply/directly by fixing the comprehension
Please see how can i get a flat result from a list comprehension instead of a nested list?
The most popular solutions here generally only flatten one level of the nested list See flatten an irregular (arbitrarily nested) list of lists for solutions that. A list of lists would essentially represent a tree structure, where each branch would constitute the same type as its parent, and its leaf nodes would represent values. In c# if i have a list of type bool
What is the fastest way to determine if the list contains a true value I don’t need to know how many or where the true value is I just need to know if one e. Is the a short syntax for joining a list of lists into a single list ( or iterator) in python
