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When the ball is going in upwards direction, its speed will be less as compared to when it comes down Gravitational force on an imaginary planet is 6 times stronger than the gravitational force of the earth This is because of the acceleration, which is produced due to the force of gravity

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In this topic, we will discuss acceleration due to gravity formula. Moreover, the equator of the earth is at a larger distance from the centre of the earth as compared to the poles. The radius of the earth is 6400 km.

The acceleration due to gravity at a height (1 20)th the radius of earth above earth's surface is 9 m/s2

Its value at a point at an equal distance below the surface of earth is ________ m/s2. The value of acceleration due to gravity is 980cms−2 What will be its value if the unit of length is kilometer and that of time is minute? Calculate the acceleration due to gravity at a point a] 64 km above and b] 32 km below the surface of earth

Given radius of earth =6400 km Acceleration due to gravity at the surface of earth = 9.8 ms−2. Find the acceleration due to gravity of the moon at a point 1000km above the moon's surface The mass of the moon is 7.4×1022kg and its radius is 1740km.

The value of acceleration due to gravity (g) by using gravitational constant and acceleration due to gravity relationship

Let the mass of the object be m We know the relationship between g and g, ⇒ g = (g×m)/ → {equation 1} the above relation is derived from newton's second law and universal gravitation law. The acceleration of freely falling bodies due the force of attraction of the other body is called acceleration due to gravity It is a constant quantity for a given attracting body at a given place

Like for earth on or near its surface, the average value of acceleration due to gravity is 9.8 m/s2 was this answer helpful? Value of effective g increases as we move from equator to north pole because on equator its value is less due to earth's rotational motion and consequent centrifugal force