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Quadrant iii would be that part of the clock face where the hours 6, 7, 8, and 9 are I am having trouble trying to figure out what exactly i need to show for the answers Finally quadrant iv (or 4) is the lower right section of the coordinate system
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Quadrant iv is that part of a clock face where the hours 3, 4, 5, and 6 are I found that opp=3, hyp= 5, and adj=4 Hope this helps you to understand the system for numbering the quadrants
Find the quadrant (1, 2, 3, or 4) containing the points on the unit circle satisfying the given conditions
Csc (t) > 0 tan (t) > 0 answer by fcabanski (1391) (show source): You can put this solution on your website I'll do the first two to show you how to solve these problems remember, the four quadrants are in these regions of the coordinate system On a coordinate plane, a curve opens down and to the right in quadrants 1 and 4
The solution region is lying in the 3rd and 4th quadrant We are given the inequalities, and using the 'zero test' i.e Thus, the graph of the inequality is towards the origin and the inequality is away from the origin Thus, we get the following.
Then i can find x
My answers are coming wrong, and i can apply no suitable rule Please help, and show working if possible. 5 people found it helpful hardiko4 report flag outlined answer If the distance between the point (4, p) and (1, 0) is 5, then the value of p is 4
2 internally lies in the fourth quadrant. Find sin2x, cos2x, and tan2x if cos=4/5 and x terminates in quad iv
